oracle数据库增删改查练习50例-答案(精)

oracle 数据库增删改查练习50例-答案

一、建表--学生表drop table student;create table student (sno varchar2(10,sname

varchar2(10,sage date,ssex varchar2(10;insert into student values('01','赵雷',to_date('1990/01/01','yyyy/mm/dd','男';insert into student values('02','钱电',to_date('1990/12/21','yyyy/mm/dd','男';insert into student values('03','孙风',to_date('1990/05/20','yyyy/mm/dd','男';insert into student values('04','李云',to_date('1990/08/06','yyyy/mm/dd','男';insert into student values('05','周梅',to_date('1991/12/01','yyyy/mm/dd','女';insert into student values('06','吴兰',to_date('1992/03/01','yyyy/mm/dd','女';insert into student values('07','郑竹',to_date('1989/07/01','yyyy/mm/dd','女';insert into student values('08','王菊',to_date('1990/01/20','yyyy/mm/dd','女';--课程表drop table course;create table course

(cno varchar2(10,cname varchar2(10,tno varchar2(10;insert into course values ('01','语文','02';insert into course values ('02','数学','01';insert into course values ('03','英语','03';

--教师表drop table teacher;create table teacher (tno varchar2(10,tname

varchar2(10;insert into teacher values('01','张三';insert into teacher values('02','李四';insert into teacher values('03','王五';

--成绩表drop table sc;create table sc (sno varchar2(10,cno varchar2(10,score

number(18,1;insert into sc values('01','01',80.0;insert into sc values('01','02',90.0;insert

into sc values('01','03',99.0;insert into sc values('02','01',70.0;insert into sc

values('02','02',60.0;insert into sc values('02','03',80.0;insert into sc

values('03','01',80.0;insert into sc values('03','02',80.0;insert into sc

values('03','03',80.0;insert into sc values('04','01',50.0;insert into sc

values('04','02',30.0;insert into sc values('04','03',20.0;insert into sc

values('05','01',76.0;insert into sc values('05','02',87.0;insert into sc

values('06','01',31.0;insert into sc values('06','03',34.0;insert into sc

values('07','02',89.0;insert into sc values('07','03',98.0;

commit;

二、查询1.1、查询同时存在"01"课程和"02"课程的情况select , ,

, , , from student s, sc sc1, sc sc2 where =

and = and = '01' and = '02';

1.2、查询必须存在"01"课程，"02"课程可以没有的情况

select t.*, _01, _02 from student t inner join (select ,

score_01, score_02 from sc a left join (select * from sc where cno = '02' b on

( = where = '01' s on ( = ;

2.1、查询同时'01'课程比'02'课程分数低的数据

select , , , , , from student s, sc sc1, sc

sc2 where = and = and = '01' and = '02' and

< ;

2.2、查询同时'01'课程比'02'课程分数低或'01'缺考的数据select , ,

, , _01, _02 from student s, (select , score_01,

score_02 from (select * from sc where cno = '01' a, (select * from sc where cno =

'02' b where (+ = t where = and (_01 < _02 or

_01 is null;

3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩select , , _score avg_score from student s, (select sno, round(avg(score,

2 avg_score from sc group by sno having avg(score >= 60 order by sno t where =

;

4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩4.1、有考试成绩，且小于60分select , , _score avg_score from student s,

(select sno, round(avg(score, 2 avg_score from sc group by sno having avg(score < 60

order by sno t where = ;

4.2、包括没有考试成绩的数据select g.* from (select , ,

nvl(_score, 0 avg_score from student s, (select sno, round(avg(score, 2 avg_score

from sc group by sno order by sno t where = (+ g where _score < 60;

5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩5.1、查询所有成绩的（不含缺考的）。select ,,_cno,_scorefrom

student s,(select sno,count(cno count_cno,sum(score sum_score from sc group by sno

order by sno c

where =

5.2、查询所有成绩的(包括缺考的。select a.s_sno, a.s_sname, nvl(a.c_cno, 0,

a.s_score from (select s_sno, s_sname, _cno c_cno, _score

s_score from student s, (select sno, count(cno count_cno, sum(score sum_score from sc

group by sno order by sno c where = (+ a

6、查询"李"姓老师的数量 （有几个老师姓李）select count(tn from (select tno,

substr(tname, 0, 1 tn from teacher where substr(tname, 0, 1 = '李' a;

7、哪些学生上过张三（老师）的课select st.* from student st, course co, teacher

te, sc where = and = and = and = '张三'

8、哪些学生没上过张三（老师）的课select * from studentminus select st.* from

student st, course co, teacher te, sc where = and = and =

and = '张三'

9、查询 '01' '02'都学过的同学的信息select st.* from student st, (select * from sc

where cno = '01' a, (select * from sc where cno = '02' b where = and =

10、查询学过编号为'01'但是没有学过编号为'02'的课程的同学的信息select st.*

from student st, ((select sno from sc where cno = '01' minus (select sno from sc where

cno = '02' a where = ;

11、查询没有学全所有课程的同学的信息11.1 学完所有课程的select st.* from

student st, (select sno, count(cno from sc group by sno having count(cno = 3 a where

= ;

11.2 没有学完所有课程的select st.* from student st,

(select sno from student minus select sno from sc group by sno having count(cno = 3

a where = ;

12、查询至少有一门课与学号为'01'的同学所学相同的同学的信息select st.*

from student st, (select distinct sno from sc where cno in (select cno from sc where sno =

'01' and sno != 1 a where = ;

13、查询和'01'号的同学学习的课程完全相同的其他同学的信息select st.* from

student st, (select sno from (select sno, count(cno CNT1 from sc group by sno a, (select

count(cno CNT2 from sc where sno = '01' b where 1 = 2 and != '01' c

where = ;

14、查询没学过"张三"老师讲授的任一门课程的学生姓名select st.* from

student st, (select sno from student minus select sno from sc where cno = (select

from teacher t, course c where = and tname = '张三' a where = ;

15、查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩select

, , _score from student st, (select sno, count(cno, round(avg(score, 2

avg_score from (select * from sc where score < 60 group by sno a where = ;

16、检索'01'课程分数小于60，按分数降序排列的学生信息select st.*, ,

from student st, (select sno, cno, score from sc where cno = '01' and score < 60

order by score desc a where = ;

17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩select

, , , , , _score from student st, (select sno,

round(avg(score, 2 avg_score from sc group by sno

order by avg_score desc a, (select * from sc where cno = '01' c, (select * from sc

where cno = '02' d, (select * from sc where cno = '03' e where = (+ and

= (+ and = (+ and = (+

18、查询各科成绩最高分、最低分和平均分：以如下形式显示：课程ID，课程name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率select

"课程编号", "课程名称", _score "最高分", _score "最低分",

_socre "平均分", e."及格率", e."中等率", e."优良率", e."优秀率" from course a,

(select cno, max(score max_score from sc group by cno b, (select cno, min(score

min_score from sc group by cno c, (select cno, round(avg(score, 2 avg_socre from sc

group by cno d, (select '01' cno, round((select count(1 from sc where cno = '01' and

score >= 60 / (select count(1 from sc where cno = '01' * 100, 2 "及格率", round((select

count(1 from sc where cno = '01' and score >= 70 and score < 80 / (select count(1 from sc

where cno = '01' * 100, 2 "中等率", round((select count(1 from sc where cno = '01' and

score >= 80 and score < 90 / (select count(1 from sc where cno = '01' * 100, 2 "优良率",

round((select count(1 from sc where cno = '01' and score >= 90 / (select count(1 from sc

where cno = '01' * 100, 2 "优秀率" from dual union select '02' cno, round((select count(1

from sc where cno = '02' and score >= 60 / (select count(1 from sc where cno = '02' * 100,

2 "及格率", round((select count(1 from sc where cno = '02' and score >= 70 and score <

80 / (select count(1 from sc where cno = '02' * 100, 2 "中等率",

round((select count(1 from sc where cno = '02' and score >= 80 and score < 90 /

(select count(1 from sc where cno = '02' * 100, 2 "优良率", round((select count(1 from sc

where cno = '02' and score >= 90 / (select count(1 from sc where cno = '02' * 100, 2 "优秀率" from dual union select '03' cno, round((select count(1 from sc where cno = '03' and

score >= 60 / (select count(1 from sc where cno = '03' * 100, 2 "及格率", round((select

count(1 from sc where cno = '03' and score >= 70 and score < 80 / (select count(1 from sc

where cno = '03' * 100, 2 "中等率", round((select count(1 from sc where cno = '03' and

score >= 80 and score < 90 / (select count(1 from sc where cno = '03' * 100, 2 "优良率",

round((select count(1 from sc where cno = '03' and score > 90 / (select count(1 from sc

where cno = '03' * 100, 2 "优秀率" from dual e where = and =

and = and = ;

19、按各科成绩进行排序，并显示排名select sno, cno, score,

rank( over(partition by cno order by score desc "名次" from sc;

select sno, cno, score, dense_rank( over(partition by cno order by score desc "名次"

from sc;

20、查询学生的总成绩并进行排名20.1 查询学生的总成绩select , ,

nvl(_score, 0 "总成绩" from student a, (select sno, sum(score sum_score from sc

group by sno order by sno b where = (+;

20.2 查询学生的总成绩并进行排名。select c."学生编号",c."学生姓名",c."总成绩",rank( over (order by c."总成绩" desc "排名"from (select "学生编号",

"学生姓名", nvl(_score, 0 "总成绩" from student a, (select sno, sum(score

sum_score from sc group by sno order by sno b where = (+ c

21、查询不同老师所教不同课程平均分从高到低显示select , ,

_score "平均分" from teacher a, course b, (select cno, round(avg(score, 2 avg_score

from sc group by cno c where = and = order by "平均分" desc;

22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩Score 重复时保留名次空缺select * from (select sno, cno, score, rank( over(partition by cno order

by score desc order_sc from sc a where _sc in (2, 3;

Score 重复时合并名次 select * from (select sno, cno, score,

dense_rank( over(partition by cno order by score desc order_sc from sc a where

_sc in (2, 3;

23 、 统 计 各 科 成 绩 各 分 数 段 人 数 ： 课 程 编 号 , 课 程 名称,"100-85","85-70","70-60","0-60"及所占百分比23.1 统 计 各 科 成 绩 各 分 数 段 人 数 ：

课 程 编 号 , 课 程 名称,"100-85","85-70","70-60","0-60"select , , b."85-100", b."70-85", b."60-70", b."0-60" from course a, (select '01' cno, (select count(1 from

sc where cno = '01' and score >= 85 and score <= 100 "85-100", (select count(1 from sc

where cno = '01' and score >= 70 and score < 85 "70-85", (select count(1 from sc where

cno = '01' and score >= 60 and score < 70 "60-70", (select count(1 from sc where cno =

'01' and score < 60 "0-60" from dual union select '02' cno, (select count(1 from sc

where cno = '02' and score >= 85 and score <= 100 "85-100", (select count(1 from

sc where cno = '02' and score >= 70 and score < 85 "70-85", (select count(1 from sc

where cno = '02' and score >= 60 and score < 70 "60-70", (select count(1 from sc where

cno = '02' and score < 60 "0-60" from dual union select '03' cno, (select count(1 from sc

where cno = '03' and score >= 85 and score <= 100 "85-100", (select count(1 from sc

where cno = '03' and score >= 70 and score < 85 "70-85", (select count(1 from sc where

cno = '03' and score >= 60 and score < 70 "60-70", (select count(1 from sc where cno =

'03' and score < 60 "0-60" from dual b where = ;

纵向显示 1(显示存在的分数段;

select , , , b.c1 from course a, (select cno, c1, '0-60' ff from (select

cno, count(1 c1 from sc where score < 60 group by cno union select cno, c1, '60-70' ff

from (select cno, count(1 c1 from sc where score >= 60 and score < 70 group by cno

union select cno, c1, '70-85' ff from (select cno, count(1 c1 from sc where score >= 70

and score < 85 group by cno union select cno, c1, '85-100' ff from (select cno, count(1 c1

from sc where score >= 85 and score <= 100

group by cno b where =

23.2 统 计 各 科 成 绩 各 分 数 段 人 数 ： 课 程 编 号 , 课 程 名称,"100-85","85-70","70-60","<60"及所占百分比横向显示select , , bb."0-60",

bb."1百分比(%", bb."60-70", bb."2百分比(%", bb."70-85", bb."3百分比(%", bb."85-100", bb."4百分比(%" from course aa, ((select '01' cno, (select count(1 from sc where

cno = '01' and score < 60 "0-60", round(((select count(1 from sc where cno = '01' and

score < 60 * 100 / (select count(1 from sc where cno = '01', 2 "1百分比(%", (select

count(1 from sc where cno = '01' and score >= 60 and score < 70 "60-70", round(((select

count(1 from sc where cno = '01' and score >= 60 and score < 70 * 100 / (select count(1

from sc where cno = '01', 2 "2百分比(%", (select count(1 from sc where cno = '01' and

score >= 70 and score < 85 "70-85", round(((select count(1 from sc where cno = '01' and

score >= 70 and score < 85 * 100 / (select count(1 from sc where cno = '01', 2 "3百分比(%", (select count(1 from sc where cno = '01' and score >= 85 and score <= 100 "85-100",

round(((select count(1 from sc where cno = '01' and score >= 85 and score <= 100 * 100 /

(select count(1 from sc where cno = '01', 2 "4百分比(%" from dual union (select '02' cno,

(select count(1 from sc

where cno = '02' and score < 60 "0-60", round(((select count(1 from sc where cno =

'02' and score < 60 * 100 / (select count(1 from sc where cno = '02', 2 "1百分比(%",

(select count(1 from sc where cno = '02' and score >= 60 and score < 70 "60-70",

round(((select count(1 from sc where cno = '02' and score >= 60 and score < 70 * 100 /

(select count(1 from sc where cno = '02', 2 "2百分比(%", (select count(1 from sc where

cno = '02' and score >= 70 and score < 85 "70-85", round(((select count(1 from sc where

cno = '02' and score >= 70 and score < 85 * 100 / (select count(1 from sc where cno = '02',

2 "3百分比(%", (select count(1 from sc where cno = '02' and score >= 85 and score <=

100 "85-100", round(((select count(1 from sc where cno = '02' and score >= 85 and score

<= 100 * 100 / (select count(1 from sc where cno = '02', 2 "4百分比(%" from dual union

(select '03' cno, (select count(1 from sc where cno = '03' and score < 60 "0-60",

round(((select count(1 from sc where cno = '03' and score < 60 * 100 / (select count(1

from sc where cno = '03', 2 "1百分比(%", (select count(1 from sc where cno = '03' and

score >= 60 and score < 70 "60-70", round(((select count(1 from sc where cno = '03' and

score >= 60 and score < 70 * 100 / (select count(1 from sc where cno = '03', 2 "2百分比(%",

(select count(1 from sc where cno = '03' and score >= 70 and score < 85 "70-85",

round(((select count(1 from sc where cno = '03' and score >= 70 and score < 85 * 100 /

(select count(1 from sc where cno = '03', 2 "3百分比(%", (select count(1 from sc where

cno = '03' and score >= 85 and score <= 100 "85-100", round(((select count(1 from sc

where cno = '03' and score >= 85 and score <= 100 * 100 / (select count(1 from sc where

cno = '03', 2 "4百分比(%" from dual bb where = ;

纵向显示

select t1.*, round( / _num * 100, 2 || '%' 百分比 from (select ,

, (case when >= 85 then '85-100' when >= 70 and < 85

then '70-85' when >= 60 and < 70 then '60-70' else '0-60' end as px,

count(1 num from Course m, sc n where = group by , , (case

when >= 85 then '85-100' when >= 70 and < 85 then '70-85' when

>= 60 and < 70 then '60-70' else '0-60' end order by , , px

t1, (select , , count(1 all_num from course m, sc n where =

group by , order by , t2 where =

24、 查询学生的平均成绩并进行排名select , , _score,

from student st, (select b.*, rownum paim from (select , round(avg(score, 2

avg_score from (select sno, nvl(, 0 score from student s, sc where =

(+ a group by order by avg_score desc b c where = ;

25、查询各科成绩前三名的记录25.1 分数重复时保留名次空缺select st.*,

, from student st, (select a.* from (select * from sc where cno = '01' order by

score desc a where rownum <= 3 union all select b.* from (select * from sc where cno =

'02' order by score desc b where rownum <= 3 union all select c.* from (select * from sc

where cno = '03' order by score desc c where rownum <= 3 d where =

25.2 分数重复时不保留名次空缺，合并名次select

,,,,,,om student st,(select

sno,cno,score,paim from (select sno, cno, score, dense_rank( over(partition by cno order

by score desc paim from sc awhere <= 3 bwhere =

26、查询每门课程被选修的学生数select cno,count(1 from sc group by cno;

27、查询出只有两门课程的全部学生的学号和姓名 select , from

student st, (select from (select sno, count(cno cn from sc group by sno a where

= 2 b where = ;

28、查询男生、女生人数select '男生人数' "男女情况", cn from (select

count(ssex cn from student where ssex = '男'union allselect '女生人数' "男女情况", cn

from (select count(ssex cn from student where ssex = '女'

29、查询名字中含有"风"字的学生信息select * from student where sname like '%风%'

31、查询1990年出生的学生名单(注：Student表中Sage列的类型是dateselect

* from student where to_char(sage,'yyyy' = '1990'

32、查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号升序排列select ,,_score

from course c,(select cno,round(avg(score,2 avg_score from sc group by cno awhere

= er by _score desc ,;

33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩select

, , _score from student st, (select sno, round(avg(score, 2 avg_score

from sc group by sno having round(avg(score, 2 >= 85 a where = ;

34、查询课程名称为"数学"，且分数低于60的学生姓名和分数select

,rom student st,(select sno, score from sc where cno = (select cno from

course where cname = '数学' and score < 60 awhere =

35、查询所有学生的课程及分数情况select st.*, , , from

student st, course c, sc where = and =

36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数；select st.*,

, , from student st, course c, sc, (select sno, min(score from sc

group by sno having min(score >= 70 a where = and = and

=

37、查询不及格的课程 select st.*,,,rom student st,course

c,(select * from sc where score < 60 awhere = =

38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名select

st.*,,,rom student st,course c,(select sno,cno,scorefrom scwhere cno

= '01' and score >= 80 awhere = =

39、求每门课程的学生人数select ,, course c,(select

cno,count(sno cn from sc group by cno awhere =

40、查询选修"张三"老师所授课程的学生中，成绩最高的学生信息及其成绩select st.*, , ,

from student st, course c, (select * from sc where score = (select max(score from

(select * from sc where cno = (select cno from course where tno = (select tno from

teacher where tname = '张三' a and cno = (select cno from course where tno = (select tno

from teacher where tname = '张三' b where = and =

41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩select

distinct , , rom sc sc1,sc sc2where = nd

!=

42、查询每门功成绩最好的前两名

select , , , , , from student st, (select sno, cno,

score, dense_rank( over(partition by cno order by score desc paim from sc a where

= and <= 2

select , , , , , from student st, (select sno, cno,

score, rank( over(partition by cno order by score desc paim from sc a where =

and <= 2

44、检索至少选修两门课程的学生学号select ,, student

st,(select sno,count(cno cn from sc group by sno having count(cno >= 2 aawhere =

46、查询各学生的年龄select st.*, (to_char(sysdate, 'yyyy' - to_char(, 'yyyy'

"年龄" from student st

47、查询本周过生日的学生select st.* from student st where to_char(,

'mmdd' between to_char(trunc(sysdate, 'iw', 'mmdd' and to_char(trunc(sysdate, 'iw' + 6,

'mmdd'

48、查询下周过生日的学生select st.* from student st where to_char(,

'mmdd' between to_char(trunc(sysdate, 'iw'+7, 'mmdd' and to_char(trunc(sysdate, 'iw' +

13, 'mmdd'

select to_char(trunc(sysdate, 'iw'+7, 'mmdd' from dual; select to_char(trunc(sysdate,

'iw'+ 13, 'mmdd' from dual;

49、查询本月过生日的学生select st.* from student st where to_char(, 'mm'

= to_char(sysdate,'mm'

50、查询下月过生日的学生select st.*from student st where to_char(, 'mm'

= to_char(add_months(trunc(sysdate,1,'mm'