admin 管理员组

文章数量: 887021


2024年2月26日发(作者:java代码中遇到请问是什么意思)

<%

rem 在ASP中实现加密与解密,加密方法:根据RSA

rem 联系:hnsoso@

Class clsRSA

Public PrivateKey

Public PublicKey

Public Modulus

Public Function Crypt(pLngMessage, pLngKey)

On Error Resume Next

Dim lLngMod

Dim lLngResult

Dim lLngIndex

If pLngKey Mod 2 = 0 Then

lLngResult = 1

For lLngIndex = 1 To pLngKey / 2

lLngMod = (pLngMessage ^ 2) Mod Modulus

' Mod may error on key generation

lLngResult = (lLngMod * lLngResult) Mod Modulus

If Err Then Exit Function

Next

Else

lLngResult = pLngMessage

For lLngIndex = 1 To pLngKey / 2

lLngMod = (pLngMessage ^ 2) Mod Modulus

On Error Resume Next

' Mod may error on key generation

lLngResult = (lLngMod * lLngResult) Mod Modulus

If Err Then Exit Function

Next

End If

Crypt = lLngResult

End Function

Public Function Encode(ByVal pStrMessage)

Dim lLngIndex

Dim lLngMaxIndex

Dim lBytAscii

Dim lLngEncrypted

lLngMaxIndex = Len(pStrMessage)

If lLngMaxIndex = 0 Then Exit Function

For lLngIndex = 1 To lLngMaxIndex

lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))

lLngEncrypted = Crypt(lBytAscii, PublicKey)

Encode = Encode & NumberToHex(lLngEncrypted, 4)

Next

End Function

Public Function Decode(ByVal pStrMessage)

Dim lBytAscii

Dim lLngIndex

Dim lLngMaxIndex

Dim lLngEncryptedData

Decode = ""

lLngMaxIndex = Len(pStrMessage)

For lLngIndex = 1 To lLngMaxIndex Step 4

lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))

lBytAscii = Crypt(lLngEncryptedData, PrivateKey)

Decode = Decode & Chr(lBytAscii)

Next

End Function

Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)

NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)

End Function

Private Function HexToNumber(ByRef pStrHex)

HexToNumber = CLng("&h" & pStrHex)

End Function

End Class

%>

<%

function Encryptstr(Message)

Dim LngKeyE

Dim LngKeyD

Dim LngKeyN

Dim StrMessage

Dim ObjRSA

LngKeyE = "32823"

LngKeyD = "20643"

LngKeyN = "29893"

StrMessage = Message

Set ObjRSA = New clsRSA

Key = LngKeyE

s = LngKeyN

Encryptstr = (StrMessage)

Set ObjRSA = Nothing

end function

function decryptstr(Message)

Dim LngKeyE

Dim LngKeyD

Dim LngKeyN

Dim StrMessage

Dim ObjRSA

LngKeyE = "32823"

LngKeyD = "20643"

LngKeyN = "29893"

StrMessage = Message

Set ObjRSA = New clsRSA

eKey =LngKeyD

s=LngKeyN

decryptstr=(StrMessage)

Set ObjRSA = Nothing

end function

dim last,first

first="sohu"

"加密前为:"&first

last=Encryptstr(first)

"加密后为"&last

"解密后为" &decryptstr(last)

%>


本文标签: 加密 代码 遇到 请问 意思